8x^2-38x+17=0

Solution for 8x^2-38x+17=0 equation:

8x^2-38x+17=0

a = 8; b = -38; c = +17;
Δ = b2-4ac
Δ = -382-4·8·17
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-30}{2*8}=\frac{8}{16}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+30}{2*8}=\frac{68}{16}
=4+1/4
$